Re: Count to 100 before next event

[Malva]

56

[Ivy]

57

[Horns]

58

[Torvallis!]

(7+2q)(7-2q) within the second modular arithmetic. (That is: q^2 = -2)

[Lady Val]

15x4

[Torvallis!]

(5+6i)(5-6i)

[Horns]

62

[Keket]

63

[Torvallis!]

2^6 aka: 0x0100, (0x00FF if you start counting from 1)

[Ivy]

8^2 +1

[Malva]

56

[Horns]

67?

[Torvallis!]

68, your count is correct. I think Malva saw the end of page 13 again?

[Horns]

Or it could've been a typo; hit 5 instead of 6!

69

[Malva]

70
and I most certainly did

[Torvallis!]

(1+i)^2 * (1-i)^2 + (7+3q) * (7-3q)

[Horns]

72

[Torvallis!]

(3+8i)*(3-8i)

[Horns]

2*37=74

[Torvallis!]

(1+2i)^2 * (1-2i)^2 * 3

[Malva]

17*2^2

[Torvallis!]

7*11

There's no imaginary decomposition for either of those numbers. >

[Ivy]

78

[Keket]

79

[Malva]

80

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